From: Michael Heerdegen <michael_heerdegen@web.de>
To: Max Brieiev <max.brieiev@gmail.com>
Cc: 59140@debbugs.gnu.org, okamsn@protonmail.com, monnier@iro.umontreal.ca
Subject: bug#59140: 29.0.50; iter-yield from lambda
Date: Sat, 16 Sep 2023 03:56:35 +0200 [thread overview]
Message-ID: <87cyyianjg.fsf@web.de> (raw)
In-Reply-To: <87v8cb9pns.fsf@gmail.com> (Max Brieiev's message of "Fri, 15 Sep 2023 22:56:07 +0300")
Max Brieiev <max.brieiev@gmail.com> writes:
> For example, this:
>
> (iter-defun my-generator ()
> (funcall (lambda () (iter-yield 5))))
>
> would be expanded by iter-defun macro into this:
>
> (...
> (let ((gen (iter-lambda () (iter-yield 5))))
> (iter-next (funcall gen))))
>
> Does it make sense?
Does it? Isn't the `let' expression equivalent to just `5'? With other
words: you don't yield from an outside generator, as far as I
understand (or am I wrong? what's the content of your "..."?).
Michael.
next prev parent reply other threads:[~2023-09-16 1:56 UTC|newest]
Thread overview: 7+ messages / expand[flat|nested] mbox.gz Atom feed top
2022-11-09 1:22 bug#59140: 29.0.50; iter-yield from lambda Michael Heerdegen
2023-09-15 19:56 ` Max Brieiev
2023-09-15 22:18 ` Stefan Monnier via Bug reports for GNU Emacs, the Swiss army knife of text editors
2023-09-16 19:39 ` Max Brieiev
2023-09-16 21:31 ` Stefan Monnier via Bug reports for GNU Emacs, the Swiss army knife of text editors
2023-09-16 1:56 ` Michael Heerdegen [this message]
2023-09-17 6:32 ` Max Brieiev
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